Differential Geometry Proof (Need a Hand)

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Homework Statement



Let alpha(t) be a regular curve. Suppose there is a point a in R^3 space s.t. alpha(t)-a is orthogonal to T(t) for all t. Prove that alpha(t) lies on a sphere.

Homework Equations


Definations:
A regular curve in R^3 is a function alpha: (a,b)-->R^3 which is of class C^k for some k (greater than or equal to) 1 and for which the time derviative does not equal zero for all t in (a,b) Note: For this book all classes will be C^3, unless stated. (it is not stated otherwise in this problem so assume C^3).

T(t)= Tangent vector field to a regular curve as defined by (d(alpha)/dt)/norm(d(alpha)/dt)).

Hints: what should be the center of the sphere?

The Attempt at a Solution



And here is where I get stuck, I have not been given a crietria for a curve to lie on a sphere (and if I had oh so many years ago I have long since forgotten it). All of my attempts so far have fallen apart due to assumptions I have had to make, which without a guide towards showing something lies on a curve, I am not sure are justified.

Just a hint, aside from the one given, is all I need to get some of my juices following. I know it isn't proper form to not show my solution; however, it won't be of use as I don't really know where I am heading with it.

Any help would be great.
 
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First find the answer to the hint given (what should be the center of the sphere?) and my hint is "if \vec{\alpha}(t)=(\alpha^1,\alpha^3,\alpha^3) lies on the sphere then what is the relation btw the coordinates \alpha^i?"
 
To prove \alpha lies on a sphere, find a point C such that |\alpha (t) - C| is a constant. 1) Do you see why this proves that \alpha lies on a sphere? 2) Can you see, with the right guess for C, how to prove that |\alpha (t) - C| is a constant?
 
It may be helpful to consider a simplfied example with a kinematical interpretation.
Consider a particle traveling on a circle. What are the relations between the displacement vector [from the origin of the circle] and the velocity vector?
 
Thanks for the help guys, I think I got it (I am going to run through it with someone else), then I will post it.

Thanks for the help.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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