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Differential Yield Stress and Von Mises Criterion

  1. Nov 30, 2014 #1
    If I have the differential yield stress σd=(σ13) for a material, what can I derive from that for use with the von mises criterion? Do I have k=0.5×(σ13) or σy in axial tension, where σ3 = 0? Essentially is my axial yield stress = σd or √3 × σd /2? (in plane stress)
  2. jcsd
  3. Dec 1, 2014 #2
  4. Dec 1, 2014 #3
    Reading this confirmed my suspicions that the axial yield would equal the differential yield and from there you would divide by √3 to get k. For tresca k would equal σd/2. In that case why report it as a differential stress? I think thats what was throwing me off. Assuming we would know to add the axial yield to any hydrostatic stress to get our maximum principal stress why give σd?
  5. Dec 1, 2014 #4
    The reason differential stress is used is that people out-of-the-know can relate to it easily.

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