Differentiate e^x and Trig Functions

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Homework Help Overview

The problem involves differentiating the expression e^x * cotx / 5sqrt(x^2), with participants discussing various differentiation techniques and clarifying the expression's components.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore using the quotient rule and product rule for differentiation, with some questioning the clarity of the expression's format. There are discussions about the complexity of the resulting equations and the potential for simplification.

Discussion Status

Some guidance has been offered regarding the use of differentiation rules, with participants sharing their thoughts on the effectiveness of the quotient versus product rule. There is an ongoing exploration of the expression's structure, particularly concerning the square root notation.

Contextual Notes

There is a noted urgency in the original post, and participants are addressing potential ambiguities in the expression's formatting, which may affect the differentiation process.

gabyoh23
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Homework Statement


Differentiate
e^x * cotx / 5sqrtx^2
[Sorry for not using the formatting things. They didn't seem to be working for me, and this is urgent!]


Homework Equations


The quotient rule seems like that's the way to go...


The Attempt at a Solution


At first I tried using the product rule on the numerator, then plugging that into the quotient rule formula, but that was needlessly complicated. So, I went straight into using the quotient rule, but I got a huge messy equation. Could anyone clarify what I SHOULD be getting?

All help is greatly appreciated!
 
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Both ways are correct. Either do product rule inside of Quotient or do Product then do Quotient. Both will be potentially messy.
 
also is that 5sqrt(x^2) or (5sqrt(x))^2 or what?
because that should simple things out for you.
 
It's 5sqrt(x^2).
Sorry about that.
 
The quotient rule is never worth remembering IMO. Just use the product rule and think of the derivative of a quotient as

[tex] \frac{d}{dx}\left( \frac{f(x)}{g(x)} \right) = \frac{d}{dx}\left(f(x) \ g(x)^{-1}\right)[/tex]

and don't forget to apply the chain rule when differentiating [tex]g(x)^{-1}[/tex].

It's too easy to forget the quotient rule on an exam, and also too easy to screw it up when you're in a rush to get everything done in 50 minutes on a midterm. The product rule and chain rule are easy though, and critical to know anyways.
 
What's the square root of x^2?

that will make it a little simpler.
 
Last edited:

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