Differentiation in Real Functions: Solving for a Differentiable Function

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Homework Statement



Show that there exists a differentiable real function:

(f(x))^5 + f(x) + x = 0

Homework Equations


??
definition of the derivative: lim (as x -> a) [f(x) - f(a)]/x-a

The Attempt at a Solution



Not really sure where to start with this one. any help would be appreciated.
 
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By (f(x))^5, did you mean the fifth power f^5(x) = (f(x))^5[/tex] or the fifth derivative f^{(5)}(x) = \frac{d^5f(x)}{dx^5}. In the first case it&#039;s not a differential equation at all and I don&#039;t see why you need the definition for derivative. <br /> <br /> Please clarify what you mean exactly, and we&#039;ll give you a push in the right direction.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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