Differentiation Map of a Complex Transformation

nautolian
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Homework Statement



Find the eigenvectors and eigenvalues of the differentiation
map C1(R) -> C1(R) from the vector space of differentiable functions
to itself.

Homework Equations





The Attempt at a Solution



Hi, I'm not entirely sure how to go about this, because would the differentiation map of this be [(1,0),(0,1)] since its from it to itself? Thanks for the help in advance.
 
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hi nautolian! :smile:
nautolian said:
Find the eigenvectors and eigenvalues of the differentiation
map C1(R) -> C1(R) from the vector space of differentiable functions
to itself.

an eigenvector is an element f of C1(R) such that Df is a scalar times f :wink:
 
High, sorry I'm still not really sure where to go with this. I mean I understand that Df=(lambda)f, but in the terms of C^1(R) does this mean that the derivative of the complex number a+bi is the same as the eigenvalue times the vector? Sorry, I'm still somewhat lost. Thanks for your help though.
 
nautolian said:
High, sorry I'm still not really sure where to go with this. I mean I understand that Df=(lambda)f, but in the terms of C^1(R) does this mean that the derivative of the complex number a+bi is the same as the eigenvalue times the vector? Sorry, I'm still somewhat lost. Thanks for your help though.

I don't think this has anything to do with complex numbers. C^1(R) usually just means differentiable real functions. You need to solve the differential equation f'(x)=λf(x).
 
okay, would that mean that there are infinite eigenvalues with associated iegenvectors equal to A*exp(lambda*x)? where A is a constant? Sorry I'm still unclear about this. Thanks for the help though!
 
nautolian said:
okay, would that mean that there are infinite eigenvalues with associated iegenvectors equal to A*exp(lambda*x)? where A is a constant? Sorry I'm still unclear about this. Thanks for the help though!

Yes, that's it.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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