Quick question.(adsbygoogle = window.adsbygoogle || []).push({});

To differentiate [tex]y = 20x (2x - 1)^6[/tex] I need to use the product rule:

[tex] y = uv \ \Rightarrow \ \frac{dy}{dx} = v\frac{du}{dx} + u\frac{dv}{dx}[/tex]

So that u = 20x and v = (2x-1)^{6}

However, do I differentiate v so that it equals 6(2x-1)^{5}or do I use:

[tex]y = [f(x)]^n \ \Rightarrow \ \frac{dy}{dx} = n[f(x)]^{n-1} f'(x)[/tex]

to give 12(2x-1)^{5}???

Cheers.

The Bob (2004 ©)

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Differentiation math problem

**Physics Forums | Science Articles, Homework Help, Discussion**