EricVT
- 165
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Alright, this is probably a really redundant question but for some reason it is giving me trouble. Let's say you are given the entropy of a black hole as:
S=\frac{8\pi^2GM^2k}{hc} (thanks Stephen Hawking)
And you have the relation between temperature and entropy/energy
\frac{1}{T}= \frac{\partial S}{\partial U} (U is energy, S is entropy)
Now if you want an expression for the temperature of a black hole in terms of it's mass and you are using U = Mc^2, then should you rewrite:
M^2 = \frac{U^2}{c^4}
S = \frac{8\pi^2GkU^2}{hc^5}
And then differentiate with respect to U to get:
\frac{1}{T} = \frac{16\pi^2GkU}{hc^5}
T = \frac{hc^5}{16\pi^2GkU}
First of all, as the ENERGY increases the TEMPERATURE decreases? Is this really possible here? I'm confused by this. Finishing the problem, though, and rewriting U = Mc^2 gives:
T = \frac{hc^3}{16\pi^2GkM}
Does this seem correct? I tried working the problem a different way by writing c in terms of U as well at the start, and differentiating that expression and got a completely different answer...one that is always negative no less. So with that approach you get constantly negative temperatures...I'm very confused by what result I should be looking for.
S=\frac{8\pi^2GM^2k}{hc} (thanks Stephen Hawking)
And you have the relation between temperature and entropy/energy
\frac{1}{T}= \frac{\partial S}{\partial U} (U is energy, S is entropy)
Now if you want an expression for the temperature of a black hole in terms of it's mass and you are using U = Mc^2, then should you rewrite:
M^2 = \frac{U^2}{c^4}
S = \frac{8\pi^2GkU^2}{hc^5}
And then differentiate with respect to U to get:
\frac{1}{T} = \frac{16\pi^2GkU}{hc^5}
T = \frac{hc^5}{16\pi^2GkU}
First of all, as the ENERGY increases the TEMPERATURE decreases? Is this really possible here? I'm confused by this. Finishing the problem, though, and rewriting U = Mc^2 gives:
T = \frac{hc^3}{16\pi^2GkM}
Does this seem correct? I tried working the problem a different way by writing c in terms of U as well at the start, and differentiating that expression and got a completely different answer...one that is always negative no less. So with that approach you get constantly negative temperatures...I'm very confused by what result I should be looking for.