ok just want a check of my work before i send it :)(adsbygoogle = window.adsbygoogle || []).push({});

differntiate the function;

f(x)=[tex]\frac{x(20-x)}{36}[/tex]

so,

f'(x)=[tex]\frac{(20x-x^2)}{36}[/tex]

f'(x)=[tex]\frac{(20-2x)}{36}[/tex]

f'(x)=[tex]\frac{(10-2x)}{18}[/tex]

Then....use the composite rule and your answer above to differntiate the function

g(x)=e^{x(20-x)/36}

g'(x)=f'(x)*e^{f(x)}

so,

g'(x)=[tex]\frac{10-2x)}{18}[/tex]*g(x)=e^{x(20-x)/36}

is this correct?

is this correct

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# Homework Help: Differntiate the function

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