- #1
ghostbuster25
- 102
- 0
ok just want a check of my work before i send it :)
differntiate the function;
f(x)=[tex]\frac{x(20-x)}{36}[/tex]
so,
f'(x)=[tex]\frac{(20x-x^2)}{36}[/tex]
f'(x)=[tex]\frac{(20-2x)}{36}[/tex]
f'(x)=[tex]\frac{(10-2x)}{18}[/tex]
Then...use the composite rule and your answer above to differntiate the function
g(x)=ex(20-x)/36
g'(x)=f'(x)*ef(x)
so,
g'(x)=[tex]\frac{10-2x)}{18}[/tex]*g(x)=ex(20-x)/36
is this correct?
is this correct
differntiate the function;
f(x)=[tex]\frac{x(20-x)}{36}[/tex]
so,
f'(x)=[tex]\frac{(20x-x^2)}{36}[/tex]
f'(x)=[tex]\frac{(20-2x)}{36}[/tex]
f'(x)=[tex]\frac{(10-2x)}{18}[/tex]
Then...use the composite rule and your answer above to differntiate the function
g(x)=ex(20-x)/36
g'(x)=f'(x)*ef(x)
so,
g'(x)=[tex]\frac{10-2x)}{18}[/tex]*g(x)=ex(20-x)/36
is this correct?
is this correct