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Homework Statement
Find the Values of B and C given this:
[tex]
\frac{(3x-18)}{(2x+1)(7x-3)}= \frac{B}{2x+1} + \frac{C}{7x-3}
[/tex]
Homework Equations
The equation given:[tex]
\frac{(3x-18)}{(2x+1)(7x-3)}= \frac{B}{2x+1} + \frac{C}{7x-3}
[/tex]
The Attempt at a Solution
My attempt:
[tex]
\frac{(3x-18)}{(2x+1)(7x-3)}= \frac{B}{2x+1} + \frac{C}{7x-3}
[/tex]
[tex]
\frac{(3x-18)}{(2x+1)(7x-3)}= \frac{B(2x+1)+C(7x-3)}{(2x+1)(7x-3)}
[/tex]
[tex]
3x-18=B(2x+1)+C(7x-3)
[/tex]
At this point I'm stuck and I think something I did was wrong.
I'd appreciate any assistance that could be provided!
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