Diffraction due to a narrorw slit

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Light with a wavelength of 490 nm creates a diffraction pattern on a screen 3.6 m away from a narrow slit, where the distance from the central maximum to the third minimum is 2 cm. To find the slit width, the relevant formula for single slit diffraction must be applied, which involves the slit width, wavelength, and the angle of the minima. The angle can be calculated using the provided distances, allowing for the determination of the slit width. Understanding the relationship between these variables is crucial for solving the problem. The discussion emphasizes the importance of using the correct formula and understanding the physical principles of diffraction.
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Homework Statement



Light of wavelength 490 nm is incident on a narrow slit. The diffraction pattern is viewed on a screen 3.6 m from the slit. The distance on the screen between the central maximum and the third minimum is 2 cm. What is the width of the slit?

Homework Equations





The Attempt at a Solution



Not sure where I need to start. Can someone help me out
 
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You should have in your notes or book, a formula ("single slit diffraction")for the angular positions of the various minima. This formula has the width of slit, the wavelength of the light, the number of the minimum counted from the centre, and the sin of the angle.
You can work out the angle from the distances given in the question, so you know all the quantities bar the width of the slit.
 

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