Diffraction Grating problem (waves and optics)

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Visible light passing through a diffraction grating with 900 slits per centimeter creates an interference pattern observed 2.58 meters away. The first-order spectrum shows maxima for two different wavelengths separated by 3.16 mm. The equation d*sin(Θ) = mλ is used, where d is calculated as 1.111*10^-5 meters. The difference in angles, ΔΘ, is derived from the separation of the maxima, leading to the calculation of the wavelength difference as approximately 1.36*10^-8 meters. This approach effectively utilizes the small angle approximation to solve the problem.
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Homework Statement



Visible light passes through a diffraction grating that has 900 slits per centimeter, and the interference pattern is observed on a screen that is 2.58m from the grating. In the first-order spectrum, maxima for two different wavelengths are separated on the screen by 3.16 mm . What is the difference between these wavelengths?

Homework Equations



d*sinΘ=mλ

The Attempt at a Solution



d = 1/90000 = 1.111*10-5

d*sin(Θ1)=λ1 and d*sin(Θ2)=λ2

using subtraction d*ΔsinΘ=Δλ (and using small angle approx d*ΔΘ=Δλ)

But I am not sure how to find ΔΘ (or how even to visualize ΔΘ)

thanks in advance.
 
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This help ?
Azd61G7.jpg

On the left is the grating, on the right is the screen.
(grating details not shown on this scale)
 
Thank you for making it clearer! i was originally thinking this but i didn't think i could calculate it since i didn't have all of the distance of the opposite side (the screen).

Is this the correct way to go about it?

Sin(ΔΘ) = sin(Θ2) - sin(Θ1)
= x/2.58 + (3.16*10-3-x)/2.58 (where x is the total distance on the screen)
= (3.16*10-3)/2.58
ΔΘ=0.001225

and λ=1.225*10-3*1.11*10-5
=1.36*10-8
 
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