Diffraction Grating problem (waves and optics)

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SUMMARY

The discussion centers on solving a diffraction grating problem involving visible light passing through a grating with 900 slits per centimeter. The interference pattern observed on a screen 2.58 meters away shows a separation of 3.16 mm between maxima for two different wavelengths. The key equations utilized include d*sin(Θ) = mλ and the small angle approximation, leading to the calculation of the difference in wavelengths, Δλ, as 1.36 x 10-8 meters.

PREREQUISITES
  • Understanding of diffraction grating principles
  • Familiarity with the wave nature of light
  • Knowledge of trigonometric functions in optics
  • Ability to apply the small angle approximation
NEXT STEPS
  • Study the derivation of the diffraction grating equation d*sin(Θ) = mλ
  • Learn about the small angle approximation in wave optics
  • Explore the impact of slit density on diffraction patterns
  • Investigate the relationship between wavelength and interference patterns
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This discussion is beneficial for physics students, educators in optics, and anyone involved in wave mechanics or optical engineering.

pondzo
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Homework Statement



Visible light passes through a diffraction grating that has 900 slits per centimeter, and the interference pattern is observed on a screen that is 2.58m from the grating. In the first-order spectrum, maxima for two different wavelengths are separated on the screen by 3.16 mm . What is the difference between these wavelengths?

Homework Equations



d*sinΘ=mλ

The Attempt at a Solution



d = 1/90000 = 1.111*10-5

d*sin(Θ1)=λ1 and d*sin(Θ2)=λ2

using subtraction d*ΔsinΘ=Δλ (and using small angle approx d*ΔΘ=Δλ)

But I am not sure how to find ΔΘ (or how even to visualize ΔΘ)

thanks in advance.
 
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This help ?
Azd61G7.jpg

On the left is the grating, on the right is the screen.
(grating details not shown on this scale)
 
Thank you for making it clearer! i was originally thinking this but i didn't think i could calculate it since i didn't have all of the distance of the opposite side (the screen).

Is this the correct way to go about it?

Sin(ΔΘ) = sin(Θ2) - sin(Θ1)
= x/2.58 + (3.16*10-3-x)/2.58 (where x is the total distance on the screen)
= (3.16*10-3)/2.58
ΔΘ=0.001225

and λ=1.225*10-3*1.11*10-5
=1.36*10-8
 

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