Engineering Digital Circuit Help: Solve for Truth Table & Boolean Function

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The discussion focuses on deriving a truth table and Boolean function for a digital circuit. The user is struggling to reconcile their Boolean function with the truth table, expressing uncertainty about their function statement. They provide a sum of products for the truth table and a complex Boolean function but are unsure of their accuracy. Another participant suggests using a Karnaugh map as a simpler method to solve the problem. The conversation emphasizes the importance of verifying both the truth table and Boolean function for consistency.
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Homework Statement


1. Derive the truth table for the circuit.
2. Derive the Boolean function directly from the circuit.
cir-1.jpg

I can't the function to agree with the truth table. I don't know what I'm doing wrong. I somewhat positive my truth table is right, but I think my function statement is wrong.

Homework Equations


None that I know of.

The Attempt at a Solution


1. Rather than show a huge truth table I'll list the sum of products-\sum(2,6,10,11,12,13,14,15)
2. F=((w(x+y)')(y'+z))'
=(w(x+y)')'(y'+z)'
=(w(x+y))(y'+z)'
=(wx+wy)+y+z'
=wxy'z'+wxyz+wx'yz'+wxyz+w'x'yz'+wxyz+w'x'y'z'+wxyz'
=wxy'z'+wxyz+w'x'yz'+wx'yz'+wxyz'
 
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fsm said:

Homework Statement


1. Derive the truth table for the circuit.
2. Derive the Boolean function directly from the circuit.
cir-1.jpg

I can't the function to agree with the truth table. I don't know what I'm doing wrong. I somewhat positive my truth table is right, but I think my function statement is wrong.

Homework Equations


None that I know of.


The Attempt at a Solution


1. Rather than show a huge truth table I'll list the sum of products-\sum(2,6,10,11,12,13,14,15)
2. F=((w(x+y)')(y'+z))'
=(w(x+y)')'(y'+z)'
=(w(x+y))(y'+z)'
=(wx+wy)+y+z'
=wxy'z'+wxyz+wx'yz'+wxyz+w'x'yz'+wxyz+w'x'y'z'+wxyz'
=wxy'z'+wxyz+w'x'yz'+wx'yz'+wxyz'

Do you know how to do a Karnaugh map? If you can write the truth table for this, that is the easiest way to go about this problem.
 
Yes I can. I'll try that.
 
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