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Problem one

Use the dilution relationship (Mi x Vi = Mf x Vf) to calculate the volume of 0.500 M NaOH needed to prepare 500 mL of .250 M NaOH.

This is my work

? L Solution = 500mL x (1L/1000mL) = .500L

? mol NaOH = .500 L Solution x (0.250 M NaOH/1 L Solution) = .125 mol NaOH

? L solution = .125 mol NaOH x (1L Solution/.500 mol NaOH) = .25

The problem then asks me to round my answer to the nearest ones place, so i have a feeling this equation has an error. Can anyone guide me to getting it right? Thanks!

Problem 2

49.22 ml of a 2.01 M naOH solution reacts completely with 40.28 mL of HCl solution according to the blanaced chemical reaction shown below:

HCl (aq) + NaOH(aq) -> NaCl(aq) + H2O(I)