Dimensional analysis and frustum of a cone

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SUMMARY

The discussion centers on the dimensional analysis of the volume of a frustum of a cone, specifically addressing the expression πh(r1² + r1r2 + r2²). The user confirms that this expression correctly represents the volume, as it aligns with the dimensional formula V = [L³]. Key insights include recognizing that the dimensions of the terms in the expression simplify correctly, and understanding the relationship between the dimensions of the radii and height of the frustum. The user concludes that the factor of 3 in the volume expression is dimensionless and thus does not affect the dimensional consistency.

PREREQUISITES
  • Understanding of geometric shapes, specifically cones and frustums.
  • Familiarity with dimensional analysis and dimensional homogeneity.
  • Knowledge of basic calculus, particularly volume calculations for solids of revolution.
  • Ability to manipulate algebraic expressions involving powers and roots.
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  • Study the derivation of the volume formula for a frustum of a cone.
  • Learn about dimensional analysis techniques in physics and engineering.
  • Explore the properties of similar geometric figures and their applications in volume calculations.
  • Investigate the implications of dimensionless quantities in mathematical expressions.
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Students in geometry, physics, and engineering, particularly those tackling problems involving the volume of solids and dimensional analysis.

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Homework Statement


Hi
Im having some difficulty with the following question:
Figure P1.14 shows a frustrum of a cone. Of the following mensuration (geometrical) expressions, which describes (a) the total circumference of the flat circular faces, (b) the volume, and (c) the area of the curved surface?
(i) π(r1 + r2)[h2 + (r1 – r2)2]1/2 (ii) 2π(r1 + r2) (iii) πh(r1^2 + r1r2 + r2^2)

and I am at part b.
Since I already know that the volume of a frustum of a cone is number (iii) I have to now prove it.
The problem is that I am having some difficulty showing it with the use of dimensional analysis.

Since V=[L^3]
how is possible that πh(r^12 + r1r2 + r2^2) is equal to it?
I know that r=L and h=L but completely confused on how to set it up
can someone point me in the right direction? I don't


thank you
 
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First start off with a cone, say cone A. If you slice off a smaller cone, say cone B, from the "top" of cone A, the solid that remains is a frustrum.

For this question, I believe r_1 is the radius of the circular base of cone A (equivalently, the larger flat circular face of the frustrum) and r_2 is the radius of the circular base of cone B (equivalently, the smaller flat circular face of the frustrum). I think the quantity h refers to the height of the frustrum.

Here are some useful hints for solving part (b) of the question:
1) How do you find the volume of a cone?
2) Cones A and B are similar; use this to express the heights of cones A and B in terms of r_1, r_2 and h.
3) Note that x^3 - y^3 \ = \ (x-y)(x^2+xy+y^2).

To clarify some of the expressions in your original post,
Option (i) \pi(r_1+r_2)\sqrt{h^2+(r_1-r_2)^2}
Option (iii) \frac{1}{3}\pi h (r_1^2+r_{1}r_{2}+r_2^2)
 
Last edited:
thank you, I think I got it
 
I'm struggling on practically this exact problem right now in my textbook.

The way I see it, I get this:

L (L2 + L2 + L2) = L3 + L3 + L3 = 3L3

But I don't see how I can arrive at L3 from my end answer...
 
Meadman23 said:
I'm struggling on practically this exact problem right now in my textbook.

The way I see it, I get this:

L (L2 + L2 + L2) = L3 + L3 + L3 = 3L3

But I don't see how I can arrive at L3 from my end answer...

I just had to answer my own question here. The 3 disappears because it's dimensionless!
 

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