Dimensional Analysis: Separating Fact from Fiction

AI Thread Summary
The discussion centers on the validity of dimensionally correct and incorrect equations in physics. Participants debate whether a dimensionally correct equation must be true and whether a dimensionally incorrect equation must be false, ultimately concluding that while some dimensionally correct equations can be incorrect, dimensionally incorrect equations cannot be true. The importance of commensurability in physical quantities is emphasized, highlighting that mixing different dimensions leads to errors. Examples illustrate that dimensionally correct equations can still lack physical validity. The conversation concludes with a consensus on the nuanced understanding of dimensional analysis in physics.
dougr81
Messages
6
Reaction score
0
I understand the concept of dimensional analysis and what it's used for etc..My question refers to a dimensionally correct or incorrect equation being true or false. Here are the possiblities:

1. A dimensionally correct equation may be correct.
2. A dimensionally incorrect equation may be correct.
3. A dimensionally correct equation must be correct.
4. A dimensionally incorrect equation must be wrong.
5. A dimensionally correct equation may be wrong.

I think all but #3 and #4 are true, but I may be wrong. Any takers?
 
Physics news on Phys.org
1 and 5 do not conflict. 2 and 4 do conflict as do 3 and 5. i would disagree with you about 2 and 4. i think 2 is wrong and 4 is correct. so i think that 1, 4, and 5 are correct. 2 and 3 are incorrect.

physical quantities that are added, subtracted, equated, or compared need to be commensurable. if you discover that you are adding apples to oranges, then it's time to stop and look for a previous mistake.
 
Last edited:
1. True
2. False
3. False
4. True
5. True

4 is true for the same reason that 2 is false. If you have a dimensionally incorrect equation then you are saying at some level that a physical unit equals a pure number. An expression like "1 m = 23.43" is never true.

EDIT: I agree with rbj who was faster on the post!
 
Thanks for the explanation you two, it makes sense! I thought a dimensionally correct eqn had to be correct but I now see why that's not true. Thanks again!
 
As an example, one can easily construct equations which are dimensionally correct, but not physically correct, such as

\vec{F} = 2m\vec{a}
 
Ben Niehoff said:
As an example, one can easily construct equations which are dimensionally correct, but not physically correct, such as

\vec{F} = 2m\vec{a}

well, if you define a Newton of force to be the force needed to accelerate 1/2 kg of mass by 1 m/s2, then it would be correct. but it's a dumb definition for the unit force.
 
I think it's easist first to watch a short vidio clip I find these videos very relaxing to watch .. I got to thinking is this being done in the most efficient way? The sand has to be suspended in the water to move it to the outlet ... The faster the water , the more turbulance and the sand stays suspended, so it seems to me the rule of thumb is the hose be aimed towards the outlet at all times .. Many times the workers hit the sand directly which will greatly reduce the water...
Back
Top