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Dipole moment for water?

  1. Apr 12, 2013 #1
    Greeting PF!!!

    http://chemwiki.ucdavis.edu/Physical_Chemistry/Atomic_Theory/Dipole_Moments

    On the website above, I found an equation for the dipole moment of water:

    "...the net dipole moment =2(1.5)xcos(104.5/2)=1.84 D."

    I understand how to calculate the bond dipole. But after calculating for the net dipole, I keep getting the same wrong answer: -1.20606

    Please tell me what I'm doing wrong!!! Thank you so much for your assistance! :]
     
  2. jcsd
  3. Apr 13, 2013 #2

    Borek

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    Staff: Mentor

    Have you tried to switch your calculator to DEG?
     
  4. Apr 13, 2013 #3
    I'm using an iPhone app. It has a tab for trig where I found cos(, so I don't think I have to switch modes. I've also used Google's scientific calculator and received the same answer. Was your answer 1.84?
     
  5. Apr 13, 2013 #4

    Borek

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    Staff: Mentor

    But you know the difference between degrees and radians, do you?
     
  6. Apr 13, 2013 #5
    Oh, wow. Totally screwed that up. Changed 104.5 radians and now I've got 1.836. Thanks Borek!!! :D
     
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