Direction of displacement,velocity and acceleration in an oscillation

AI Thread Summary
In simple harmonic motion, the direction of displacement, velocity, and acceleration can be determined based on the chosen coordinate system, which is arbitrary. For example, in a vertical pendulum, one can define upward as positive and downward as negative, or vice versa, without affecting the physics. Acceleration is always directed towards the equilibrium point, while velocity depends on the position relative to that point. The key takeaway is that the assignment of positive or negative values is a matter of convention and does not impact the underlying motion. Understanding this flexibility can simplify analysis in oscillatory systems.
hikarigenzo
Messages
6
Reaction score
0
Hi,good morning. I encountered a problem regarding simple harmonic motion. I have seen the graphs of displacement, velocity and acceleration in an oscillation. How to determine the Direction of displacement,velocity and acceleration in an oscillation? I really have no idea

Thanks
 
Physics news on Phys.org
hi hikarigenzo! :wink:
hikarigenzo said:
How to determine the Direction of displacement,velocity and acceleration in an oscillation?

i don't understand what you're asking about :confused:

can you give an example? :smile:
 
Simple harmonic motion is defined (in one way) as the motion resulting when a force is proportional to a displacement and directed back towards the equilibrium point.
Displacement is a vector... distance from equilibrium point.
Acceleration is proportional to force (a=F/m) and is therefore directed towards the equilibrium point
Velocity... depends on position
 
Thanks for the replies, I should rephrase my question. The positive or negative sign in displacement in the oscillation depends on what? For example, a pendulum that oscillates vertically, how do we give the positive or negative? Is it based on the direction like upwards positive and downwards negative or positive is given to the position above the equilibrium? Thanks. I reply quite slow because I am now preparing for exam.
 
hi hikarigenzo! :smile:
hikarigenzo said:
… For example, a pendulum that oscillates vertically, how do we give the positive or negative? Is it based on the direction like upwards positive and downwards negative or positive is given to the position above the equilibrium?

for a pendulum, it's arbitrary …

you can make left positive, or you can make right positive, it makes no difference

for a bungee jumper, you'd make up positive, simply because making down positive would be annoying (but you could make down positive if you really wanted to)

for a spring, you'd usually make extension positive, but you don't have to, and if two springs are joined together, you often make extension positive for one and extension negative for the other

to sum up …

it's arbitrary, don't worry about it! :biggrin:
 
tiny-tim said:
hi hikarigenzo! :smile:


for a pendulum, it's arbitrary …

you can make left positive, or you can make right positive, it makes no difference

for a bungee jumper, you'd make up positive, simply because making down positive would be annoying (but you could make down positive if you really wanted to)

for a spring, you'd usually make extension positive, but you don't have to, and if two springs are joined together, you often make extension positive for one and extension negative for the other

to sum up …

it's arbitrary, don't worry about it! :biggrin:


Thanks. I got it
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Hello everyone, Consider the problem in which a car is told to travel at 30 km/h for L kilometers and then at 60 km/h for another L kilometers. Next, you are asked to determine the average speed. My question is: although we know that the average speed in this case is the harmonic mean of the two speeds, is it also possible to state that the average speed over this 2L-kilometer stretch can be obtained as a weighted average of the two speeds? Best regards, DaTario
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?

Similar threads

Back
Top