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Direction of force using right hand rule

  1. Oct 15, 2007 #1
    1. The problem statement, all variables and given/known data

    [​IMG]

    2. Relevant equations

    There are many variations on the right hand rule, but I'm most confortable with the following. Current is in the direction of thumb, B field is in direction of fingers and F shoots out of the palm

    3. The attempt at a solution

    I can find the magnitude easily using F=BiLsin(theta). I get 3N. Can someone just confirm that theta is the angle between B and i? I'm not sure how to find the direction with the right hand rule in such a case (where there is an angle between B and I). For reference, the answer is into the page.
     
  2. jcsd
  3. Oct 15, 2007 #2

    Hootenanny

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    Sounds good to me
    This right-hand rule tells you the direction of the magnetic field created by the wire, not the direction of the force on the wire. See this page <http://www.molecularexpressions.com/electromag/electricity/generators/index.html> for more information. The rule you need is in figure 9.
     
  4. Oct 15, 2007 #3
    left hand rule? never heard of such a thing!
    Are you aware of any other methods to find direction of force using right hand rules?
     
  5. Oct 15, 2007 #4

    Doc Al

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  6. Oct 15, 2007 #5

    learningphysics

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    Go ahead and use the right hand rule that you wrote... you should get your palm facing into the page...
     
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