Dirichlet's Approximation Theorem not working for n=8 and α= pi?

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SUMMARY

Dirichlet's Approximation Theorem asserts that for any real number α and positive integer n, there exist integers a and b such that |aα - b| < 1/n. In the discussion, the user questioned the application of this theorem for α = π and n = 8, struggling to find suitable integers a and b. The confusion stemmed from overlooking the absolute value in the inequality, which is crucial for correctly applying the theorem. Upon reevaluation, the user acknowledged the importance of the absolute value, indicating that the theorem holds true even in this case.

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Dirichlet's Approximation Theorem not working for n=8 and α= pi?

I am reading a number theory textbook that states Dirichlet's Approximation Theorem as follows:

If α is a real number and n is a positive integer, then there exists integers a and b

with 1≤ a ≤ n such that |aα-b|< 1/n .

There is a proof of this theorem given in the text as well.

My question is if this theorem is suppose to be true for all real numbers α and positive integers n, then how come I cannot find integers a and b satisfying this inequality for α= pi and n = 8?

In this case since a is restricted to 1≤ a ≤ 8 it is easy to look for b by trying all 8 values for a:

1* pi = 3.14159...
2* pi = 6.28319...
3* pi = 9.42478...
4* pi = 12.5664...
5* pi = 15.708...
6* pi = 18.8496...
7* pi = 21.9911...
8* pi = 25.1327...

since "b" must also be an integer it is clear that the possibilities for b are 3,6,9,12,15,18,21,25.
However, none of these satisfy the inequality.

Since 1/8 = .125 the decimal values of the numbers I listed above for all the possible values of a should be less than .125 in one of the cases...but this does not happen. How can this be? I figure I must be overlooking something or computing something incorrectly because the theorem clearly states that such a, b can be found for all positive n and real α.
 
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Note it says |aα-b|< 1/n instead of (aα-b) < 1/n.
The difference is subtle but crucial. Now look again at 7*pi.
 
I completely overlooked the absolute value sign. Thank you for pointing this out!
 

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