Discover the Solution for tan(x)=sin(2x) in Just a Few Simple Steps!

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Homework Help Overview

The discussion revolves around solving the equation tan(x) = sin(2x), which involves trigonometric identities and equations.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore various methods to approach the problem, including expressing both sides in terms of sine and cosine, plotting for intersection points, and using trigonometric identities.

Discussion Status

There are multiple lines of reasoning being explored, with some participants suggesting different methods such as plotting and using identities. Guidance has been offered regarding the potential accuracy of certain approaches, but no consensus has been reached on a single method.

Contextual Notes

Participants question whether certain methods are necessary to find all solution points and express caution about potentially discarding solutions during the process.

princiebebe57
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How do you find the solution tan(x)=sin(2x)? :confused:
 
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Can you express both sides in terms of sin(x) and cos(x)? That might be a good place to start.
 
No...do i have to do that to find all the solution points?
 
princiebebe57 said:
No...do i have to do that to find all the solution points?

You could plot them and look for the intersection points.
But cristo's suggestion would probably yield more accurate ["closed form"] answers. (Be careful not to inadvertently throw away solutions.)
 
Last edited:
You can easily do it using the fact that:

[tex] \begin{array}{l}<br /> \tan x \equiv \frac{{\sin x}}{{\cos x}} \\ <br /> \sin (2x) \equiv 2\sin x\cos x \\ <br /> \end{array}[/tex]
 
square both sides...then make use of (a-b)^2 = (a+b)(a-b)
 
unscientific said:
square both sides...then make use of (a-b)^2 = (a+b)(a-b)

um...
(a-b)^2 = a^2 - 2ab + b^2
a^2 - b^2 = (a+b)(a-b)
 

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