Discover the Speed of Sound on a New Planet | Harmonics & Tube Type Explained

  • Thread starter Thread starter MissB16
  • Start date Start date
  • Tags Tags
    Harmonics
AI Thread Summary
The crew on a new planet measured the speed of sound using a 50cm tube, finding resonant frequencies at 1620Hz and 1980Hz, resulting in a calculated speed of sound at 360 m/s. The discussion revolves around determining the harmonics associated with these frequencies and identifying the type of tube used, which is suggested to be open/closed. Participants express confusion over the formulas needed to calculate the harmonics and seek clarification on how to derive them. Key resources are shared to assist in understanding the relationship between frequency and harmonics for different tube types. The conversation emphasizes the importance of using the correct formulas to arrive at the harmonic numbers.
MissB16
Messages
3
Reaction score
0
I cannot figure this out! Please help!
Q: A Spaceship lands on a new planet. The crew decides to measure the speed of sound by blowing across one end of a tube. The tube is 50cm long, and the crew finds one resonant frequency at 1620Hz and the next resonant frequency at 1980Hz. What is the speed of sound? What is the number of each of the harmonics they found? What type of tube is the crew using- open/open, or open/closed?


I found the speed to be 360 m/s, but I have no idea how to find the harmonics! I don't know where to start! Help!
 
Physics news on Phys.org
How did you find the speed?

What's the formula for the harmonics for each type of tube?
 
I found the speed by the equation v=lambda*f which both frequencies came out to 360

I'm not sure what the formulas are for the tubes...that's my problem. I don't know how to go about finding the harmonics. Hopefully you physics genius's can help me.
 
Last edited by a moderator:
Honestly 360 is what it says on my answer key and I subtracted 1980 from 1620 so I found lambda by V/f=lambda... the answer key says it's the 9th and 11th harmonics with a open/closed tube...I just need an explanation of how they got that answer.
 
MissB16 said:
Honestly 360 is what it says on my answer key
I'm not disputing the answer, only how you arrived at it. The way to get the answer is to use the formulas for the open and open/closed air columns that are in the links I gave you.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top