Discover the Sum of an Infinite Series: A Refresher

duki
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Homework Statement



Find the sum of the infinite series: 405-270+180-120+80...

Homework Equations



??

The Attempt at a Solution



I know there's a formula for this but I can't remember it. Could someone refresh my memory?
 
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You'll need to start by finding the pattern between successive terms in the series... call the first term a_0=405 , the 2nd term a_1=-270 etc... so that the series can be represented as:

405-270+180-120+80 \ldots=a_0+a_1+a_2+a_3+a_4 \ldots=\sum_{n=0}^{\infty} a_n

There should be any easy to spot relationship between terms in the series...can you spot it?
 
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Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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