Discovering Patterns in the Difference of Squares Equation

AI Thread Summary
The discussion focuses on identifying patterns in the difference of squares equation through various algebraic expressions. Participants analyze how terms like (a+b+c)(a+b-c) and (a+b+c)(a-b-c) reveal compensatory relationships between variables, leading to predictable outcomes in the resulting equations. The signs of the results, particularly in terms like -2bc, are explored to understand their derivation from the structure of the expressions. The conversation also touches on the grouping of terms to clarify the relationships further. Overall, the thread emphasizes the exploration of algebraic patterns and their implications in understanding the difference of squares.
rocomath
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I'm looking for patterns and if you can add to things I noticed before working it out, that would be good :-]

1. (a+b+c)(a+b-c)=a^2+b^2+c^2+2ab

I noticed that b+c and b-c compensated for each other.

2. (a+b+c)(a-b-c)=a^2-b^2-c^2-2bc

a+b and a-b compensated for each other and the fact that it's b+c and -b-c, is the reason that it was -2bc?

3. (a+b-c)(a-b+c)=a^2-b^2-c^2+2bc

a+b and a-b compensated for each other, Now I figured from problem 2 that it would be 2bc again, but I didn't predict the sign correctly?
 
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Not sure I will be helpful here but all I can see is that
rocophysics said:
2. (a+b+c)(a-b-c)=a^2-b^2-c^2-2bc

a+b and a-b compensated for each other and the fact that it's b+c and -b-c, is the reason that it was -2bc?

(a+b+c)(a-b-c)==(a+(b+c))(a-(b+c))=(a)^2-(b+c)^2

and the same for the 3rd one.

for the first one:
<br /> (a+b+c)(a+b-c)((a+b)+c)((a+b)-c)

EDIT: oh wait...that is not what you were talking about...my bad
 
rock.freak667 said:
EDIT: oh wait...that is not what you were talking about...my bad
Nope, lol. But I didn't even think about what you were doing (grouping then putting it in a more visible manner). Thanks, still helped!
 
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I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
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