Discrete Math- Irrational numbers, proof or counterexample

abjf9299
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Homework Statement



Determine if the statement is true or false. Prove those that are true and give a counterexample for those that are false.

If r is any rational number and if s is any irrational number, then r/s is irrational.

Homework Equations



A rational number is equal to the ratio of two other numbers.
An irrational number can't be expressed as the ratio of two other numbers.


The Attempt at a Solution



I said that this statement is false. As my counterexample, I set r = 0 and s = (2)^1/2 .

r/s then equals 0 which is rational.


I have seen several people give different answers to this problem (our professor let's us consult with each other on the homework). Am I right? If I am wrong, could someone give me a proof for this problem?
 
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abjf9299 said:
If r is any rational number and if s is any irrational number, then r/s is irrational.

You're correct. To prove this is false, you need to provide a counterexample for one situation, which you have done. By different answers though, what do you mean? Do some people think it's true, or are they providing different counterexamples? If they're just providing different counterexamples, there's nothing wrong with that.
 
Thanks for the answer! By different answers I mean they think it's true and provided "proofs" to support their assertions, but I know where they made their mistakes now. Thanks again for your help!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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