Discussion question from university physics

AI Thread Summary
When an object is dropped from a height, the time it takes to reach the ground is influenced by the height and gravitational acceleration. The equation for displacement, displacement = V0t + 0.5g(t)^2, is essential for solving these problems. The discussion revolves around determining the time it takes for an object dropped from three times the original height, with some participants suggesting that the answer is sqrt(3)T. Others are exploring various heights to understand the relationship between height and time more clearly. The conversation emphasizes the importance of correctly setting up proportions to find the solution.
hagglebaby
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Homework Statement


When you drop an object from a certain height, it takes time T to reach the ground with no air resistance. If you dropped it from 3 times that height, how long (in terms of T) would it take to reach to the ground?


Homework Equations



displacement=V0t+.5g(t)2

The Attempt at a Solution



i got T=sqrt2 and T=sqrt6 but now I'm stuck on how to set up the next proportion. Also would like to see how you started this one.
 
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hagglebaby said:

Homework Statement


When you drop an object from a certain height, it takes time T to reach the ground with no air resistance. If you dropped it from 3 times that height, how long (in terms of T) would it take to reach to the ground?


Homework Equations



displacement=V0t+.5g(t)2

The Attempt at a Solution



i got T=sqrt2 and T=sqrt6 but now I'm stuck on how to set up the next proportion. Also would like to see how you started this one.

Perhaps you could consider the case of dropping a mass , on Earth where g = 9.8, from a height of 1 m and 3 m then 8 m and 24 m and see if that gives you any hints.
 
thank you! I think the answer is sqrt3
 

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