Disintegration Energy of Beta Plus Decay

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xoxomae
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Homework Statement


The radionuclide 11C decays according to
116C → 115B + e+ + v
Show that the disintegration energy is given by
Q = (mC - mB - 2me) c2

Homework Equations


Q = (mi - mf) c2

The Attempt at a Solution


[/B]
Q= (mC - mB - me) c2

Im probably missing something obvious but I can't see where the 2me comes from.
 
on Phys.org
But that leads me to
Q = ((mC+6mE) - (mB + 5mE + mE))c2

Which gives me
Q= (mC + mB)c2
 
Ah i think I understand

Q = ((mC- 6mE) - (mB - 5mE + mE))c2

Q = (mC - mB - 2me) c2

Is this right?