Disintegration Energy of Beta Plus Decay

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Homework Help Overview

The discussion revolves around the disintegration energy of beta plus decay, specifically focusing on the decay of the radionuclide 11C into 11B, a positron, and a neutrino. Participants are exploring the relationship between atomic and nuclear masses in the context of calculating the disintegration energy.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to derive the disintegration energy using the mass-energy equivalence principle. There is a focus on understanding the distinction between atomic and nuclear masses, with some questioning how to account for the mass of electrons in the calculations.

Discussion Status

The discussion is active, with participants sharing their reasoning and adjustments to the formula for disintegration energy. There is acknowledgment of a potential misunderstanding regarding the mass terms, and some participants express clarity on the correct formulation after further exploration.

Contextual Notes

Participants are navigating the implications of using atomic versus nuclear masses, and there is a specific focus on how to incorporate the mass of electrons into the calculations. The original poster expresses uncertainty about the derivation of the factor of 2me in the energy equation.

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Homework Statement


The radionuclide 11C decays according to
116C → 115B + e+ + v
Show that the disintegration energy is given by
Q = (mC - mB - 2me) c2

Homework Equations


Q = (mi - mf) c2

The Attempt at a Solution


[/B]
Q= (mC - mB - me) c2

Im probably missing something obvious but I can't see where the 2me comes from.
 
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The key is to remember that the given masses mC and mB are atomic masses, not nuclear masses.
 
But that leads me to
Q = ((mC+6mE) - (mB + 5mE + mE))c2

Which gives me
Q= (mC + mB)c2
 
To get the nuclear mass of the carbon, should you add 6 electrons to the atomic mass?
 
Ah i think I understand

Q = ((mC- 6mE) - (mB - 5mE + mE))c2

Q = (mC - mB - 2me) c2

Is this right?
 
Looks right. Good.
 
Thank You :)
 

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