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Displacement in simple harmonic motion

  1. Nov 30, 2004 #1
    i have a problem i am working on and i am just not sure how to do it i was looking for some help i will state the problem then explain the way i am trying to do it. thanks for any help in advance.

    A 0.27 kg mass is suspended on a spring that stretches a distance of 4.9 cm. The mass is then pulled down an additional distance of 12.5 cm and released. What's the displacement from the equilibrium position with the mass attached (in cm) after 0.42 s? Take up to be positive and use g = 9.81 m/s2.

    i think the equation for such a problem is Y(t)=-ACosWT
    but all i have is a mass distance and distance the spring stretches i need to find the spring constant and the amplitude then i think i can solve this problem but i am not sure can anyone help?
  2. jcsd
  3. Nov 30, 2004 #2

    James R

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    If the mass stretches the spring by 4.9 cm, then

    [tex]mg = kx[/tex]

    This lets you calculate k, the spring constant.

    The angular frequency is then:

    [tex]\omega = \sqrt{k/m}[/tex]
  4. Nov 30, 2004 #3

    Dr Transport

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    assume that the mass moves in a sinusoidal motion [tex] A\sin(\omega t) [/tex] where [tex] A [/tex] is the initial displacement.
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