Distance from sources of different intensity to get same loudness

In summary, the conversation discusses a point source of sound emitting energy in all directions at a constant rate and a person listening at a distance of 8m. If the intensity of the source is halved, the person must be at a distance of 4√2m from the source to perceive the sound as loud as before. The formula used is I = P/4∏r^{2}, where I is intensity, P is power, and r is distance.
  • #1
coconut62
161
1

Homework Statement



A point source of sound emits energy equally in all directions at a constant rate and a person 8m from the source listens. After a while, the intensity of the source is halved. If the person wishes the sound to seem as loud as before, how far should he be now from the source?

A) 2m B) 2√2m C) 4m D) 4√2m

Homework Equations



Intensity (proportional sign) 1/distance[itex]^{2}[/itex]

Intensity (proportional sign) amplitude (not sure if needed)

The Attempt at a Solution



Answer: D

I = k/d[itex]^{2}[/itex] , where k is a constant.

I= k/8[itex]^{2}[/itex]

k = 64 I

(new I) x (new d[itex]^{2}[/itex]) = 64 I

(0.5 I) x new d[itex]^{2}[/itex] = 64I

new d[itex]^{2}[/itex]= 128

new d = 8√2 (no answer)

Sounds not very logical, but I don't know how am I wrong. Please explain to me.
 
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  • #2
In your expression I = k/d^2 what symbol represents the intensity of the source?

Your answer is obviously wrong. The naswer has to be < 8m!
 
  • #3
I represents intensity.
 
  • #4
The intensity of the source does not depend on distance from the source.
Review your formulas. You must have one that relates the power emitted by the source with the intensity received at a given distance.
 
  • #5
coconut62 said:
I represents intensity.

No, I represents intensity at the location d. In other words, I = I(d).
 
  • #6
I think this is the formula needed:

Intensity = Power/4∏r[itex]^{2}[/itex]

So the intensity of the sound where the person stood was P/256∏.

It is now halved. So the power gets halved too.

P= 128∏I

since P = 4∏r[itex]^{2}[/itex]I

128∏I=4∏r[itex]^{2}[/itex]I

r=4√2

Please correct me if I'm wrong.
 
  • #7
coconut62 said:
i think this is the formula needed:

Intensity = power/4∏r[itex]^{2}[/itex]

so the intensity of the sound where the person stood was p/256∏.

It is now halved. So the power gets halved too.

P= 128∏i

since p = 4∏r[itex]^{2}[/itex]i

128∏i=4∏r[itex]^{2}[/itex]i

r=4√2

please correct me if I'm wrong.

a-ok!
 

What is the relationship between distance and loudness?

The relationship between distance and loudness is an inverse square law, meaning that as the distance from a sound source increases, the loudness decreases exponentially.

How does the intensity of a sound source affect the distance at which it is heard?

The intensity of a sound source directly affects the distance at which it can be heard. A higher intensity sound can be heard at greater distances compared to a lower intensity sound.

What is the decibel scale and how is it related to sound intensity?

The decibel scale is a logarithmic scale used to measure sound intensity. It is related to sound intensity in that every 10 decibels represents a tenfold increase in sound intensity.

What factors can affect the loudness of a sound at a certain distance?

The loudness of a sound at a certain distance can be affected by the intensity of the sound source, the frequency of the sound, the direction of the sound, and any obstacles or barriers between the source and the listener.

How can the distance from a sound source be calculated to achieve a desired loudness?

The distance from a sound source can be calculated using the inverse square law and the decibel scale. By knowing the desired loudness and the intensity of the sound source, the distance can be calculated using the formula: Distance = (Intensity/desired loudness)^(1/2).

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