Calculating Distance Fallen for a Dropped Object

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To calculate the distance fallen by a stone dropped from rest, the appropriate equation is x = x_0 + v_0 t + (1/2) a t^2, where a is the acceleration due to gravity (9.8 m/s²). For the first second, substituting the values gives x = 0 + 0 + (1/2)(9.8)(1)², resulting in a distance of 4.9 meters. To find the distance fallen in subsequent seconds, the same formula can be applied with t values of 2 and 3 seconds respectively. The discussion emphasizes the importance of using the correct equations for calculating distances in free fall. Understanding these calculations is crucial for solving similar physics problems.
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Homework Statement


A stone is dropped from rest. Calculate the distance fallen during the first second. Calculate the distance fallen during the second second and third second, etc.

Homework Equations


d = (Vf^2 - Vo^2) / (2*a)


The Attempt at a Solution


a= 9.8 m/s^2
?
I don't know what to do please help me solve this
 
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This equation may be more helpful.

x = x_0 + v_0 t + (1/2) a t^2
 
so
x= 0+0+1/2(9.8)(1)^2
 
Yes, that looks correct.
 
Thank you !
 
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