Calculating Distance Fallen for a Dropped Object

  • Thread starter Thread starter lalahelp
  • Start date Start date
AI Thread Summary
To calculate the distance fallen by a stone dropped from rest, the appropriate equation is x = x_0 + v_0 t + (1/2) a t^2, where a is the acceleration due to gravity (9.8 m/s²). For the first second, substituting the values gives x = 0 + 0 + (1/2)(9.8)(1)², resulting in a distance of 4.9 meters. To find the distance fallen in subsequent seconds, the same formula can be applied with t values of 2 and 3 seconds respectively. The discussion emphasizes the importance of using the correct equations for calculating distances in free fall. Understanding these calculations is crucial for solving similar physics problems.
lalahelp
Messages
74
Reaction score
0

Homework Statement


A stone is dropped from rest. Calculate the distance fallen during the first second. Calculate the distance fallen during the second second and third second, etc.

Homework Equations


d = (Vf^2 - Vo^2) / (2*a)


The Attempt at a Solution


a= 9.8 m/s^2
?
I don't know what to do please help me solve this
 
Physics news on Phys.org
This equation may be more helpful.

x = x_0 + v_0 t + (1/2) a t^2
 
so
x= 0+0+1/2(9.8)(1)^2
 
Yes, that looks correct.
 
Thank you !
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »

Similar threads

A ball is dropped from the top of a building....
Replies
6
Views
2K
Relating acceleration to distance and time
Replies
5
Views
3K
Relationship between speed, distance, and time
Replies
1
Views
1K
What Determines the Meeting Point of Two Falling Stones?
Replies
5
Views
2K
How Fast Was the Second Stone Thrown to Match the First at the Cliff Base?
Replies
2
Views
2K
How Fast Should the Second Stone Be Thrown to Hit the Ground Simultaneously?
Replies
6
Views
5K
Potential and Kinetic energy equations including drag coefficient
Replies
1
Views
1K
Solving for potential energy after time t.
Replies
4
Views
1K
A block dropping onto a spring system
2
Replies
58
Views
2K
1-dimensional kinematics - final velocity of 2 trains in opposing direction
Replies
3
Views
849

Hot Threads

Recent Insights

Back
Top