- #1
ucdawg12
- 10
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Here is the question: A large cannon is fired over level ground at an angle of 30 degrees above the horizontal. The muzzle velocity is 980m/s. What horizontal distance (in meters) will the projectile travel before striking the ground?
I know the answer, it is 85,000 meters, however I am having trouble arriving at that answer myself. Here is what I am doing. First I find how long it is in the air, I find the 980sin(30) to find the vertical velocity of 490. then I use the v=v(initial) + at, 0 = 490 +(-9.8t), t=50. Then to find the horizontal distance I do 980cos(30) = 850. Then v=x/t, vt=x, 850(50)=43000. But that isn't the right answer. Does anyone know what I did wrong? Thanks
I know the answer, it is 85,000 meters, however I am having trouble arriving at that answer myself. Here is what I am doing. First I find how long it is in the air, I find the 980sin(30) to find the vertical velocity of 490. then I use the v=v(initial) + at, 0 = 490 +(-9.8t), t=50. Then to find the horizontal distance I do 980cos(30) = 850. Then v=x/t, vt=x, 850(50)=43000. But that isn't the right answer. Does anyone know what I did wrong? Thanks