Distribution of mass and angular momentum

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SUMMARY

The discussion centers on the impact of mass distribution on the angular momentum of two cylinders with equal weight and size. Cylinder one has its mass distributed around an outer radius, while cylinder two has it distributed around an inner radius. The moment of inertia (MI) for cylinder two is lower due to the mass being closer to the axis of rotation, resulting in less angular momentum for a given rotation rate. To accurately calculate angular momentum (L), one must know the specific mass distribution of the cylinders.

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  • Understanding of moment of inertia (MI) calculations
  • Familiarity with angular momentum concepts
  • Basic knowledge of rotational dynamics
  • Ability to perform integration for mass distribution
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If I had two cylinders of equal weight and size, but cylinder one had the weight distributed around an outer radius and cylinder two had it distributed around an inner one, would it change their angular momentum going down an incline? Would they be equal, or would cylinder two have greater momentum? And how would I reflect this when solving for L?
 
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The moment of inertia of a body is calculated by integrating dm r2, where dm is an element of mass and r is its distance from the axis of rotation. Thus, when mass is close to the axis (your cylinder two), the MI is less, so for a given rotation rate the angular momentum is less.
To calculate it you will need to know the actual mass distribution.
 
Thanks!

For the problem itself, I will have numbers for the mass, which is distributed equally around the center of the cylinder, so will be able to calculate the actual momentum.
 

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