Distribution of weighted Normal Distributions

TOOP
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You created a random number generator that works as follows:
With probability p it selects a number X from the standard normal distribution N(0,1), and
with complimentary probability (1-p) it selects a random number X from an off-central
normal distribution N(5, 1). Write the distribution function of X.



How would you attempt this.
Obviously the variance increases.
and the mean is a weighted average of the two.
but as far as getting fx(x) I am stumped.
Is it correct to add the two distributions together and simplify?
(p)*N(0,1) + (1-p)*N(5,1)
using the gaussian equation?
 
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looks reasonable to me - when you have a discrete probability to realize a given distribution, you can just add the distributions together weighted by their probabilties

if it doubt try it, this would be pretty simple to implement in excel as a check
 
TOOP said:
You created a random number generator that works as follows:
With probability p it selects a number X from the standard normal distribution N(0,1), and
with complimentary probability (1-p) it selects a random number X from an off-central
normal distribution N(5, 1). Write the distribution function of X.



How would you attempt this.
Obviously the variance increases.
and the mean is a weighted average of the two.
but as far as getting fx(x) I am stumped.
Is it correct to add the two distributions together and simplify?
(p)*N(0,1) + (1-p)*N(5,1)
using the gaussian equation?

Yes, it is correct. However, it won't simplify. The final result is NOT itself a Gaussian, or anything like it.

RGV
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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