Divergence Theorem-Electromagnetism

  • Thread starter Thread starter sclatters
  • Start date Start date
  • Tags Tags
    Divergence
sclatters
Messages
13
Reaction score
0

Homework Statement


oj2xdi.png



Homework Equations


The divergence theorem is quoted on the problem sheet.


The Attempt at a Solution


I am struggling with the last question (2)c)). I have tried to put the continuity equation into the divergence theorem and have got:

S J.ds=-d/dt∫V ρdV

But I'm not sure if I can just sub it in in this way. Do I then need to set up an intergral to get the final solution? I am not really sure what form the answer will be in.

Thanks.
 
Physics news on Phys.org
sclatters said:
I am struggling with the last question (2)c)). I have tried to put the continuity equation into the divergence theorem and have got:

S J.ds=-d/dt∫V ρdV

But I'm not sure if I can just sub it in in this way. Do I then need to set up an intergral to get the final solution? I am not really sure what form the answer will be in.

Hello, sclatters. I'm not sure what you mean when you say "I'm not sure if I can just sub it in in this way."

But, it looks to me that you have the result! No further calculation should be necessary. You just need to interpret the meaning of the left and right sides of the equation.
 
  • Like
Likes 1 person
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top