idea2000
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So, I've been reading a whole bunch of different answers to this online. Some people say yes, some people say no. I'm totally confused...
That didn’t address my specific question to you.idea2000 said:Well, supposedly there is a paradox here, where the free fall frame doesn't see the electron radiate, but the lab frame does. However, I just looked on wikipedia, and supposedly the paradox is resolved by using the equivalence principle.
It depends on how "radiation" is defined. In principle, it is straightforward (but not necessarily easy) to calculate the EM field around the charge falling in a gravitational field. The debate is about should such EM field be called "radiation".idea2000 said:So, I've been reading a whole bunch of different answers to this online. Some people say yes, some people say no. I'm totally confused...
bobob said:Not to an observer falling with the charge. Here is a link to an article that addresses that question in depth: "Radiation from a Uniformly Accelerated Charge and the Equivalence Principle," Parrott, S.,
https://arxiv.org/abs/gr-qc/9303025
We argue that purely local experiments can distinguish a stationary charged particle in a static gravitational field from an accelerated particle in (gravity-free) Minkowski space. Some common arguments to the contrary are analyzed and found to rest on a misidentification of “energy”.
Does Einstein’s Equivalence Principle hold for charged particles? We cannot definitively answer this because a mathematically precise statement of the “equivalence principle” seems elusive — most statements in the literature are not sufficiently definite to be susceptible of proof or disproof. However, we do conclude that most usual formulations seem not to hold in any direct and obvious way for charged particles.
idea2000 said:So, I've been reading a whole bunch of different answers to this online. Some people say yes, some people say no. I'm totally confused...