Does a Blackbody at 200K Emit Twice as Much Radiation?

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A blackbody at 200K does not emit twice as much radiation as at 100K. The Stefan-Boltzmann Law states that the total power radiated is proportional to the fourth power of the temperature (P ∝ T^4). Therefore, the correct calculation shows that a blackbody at 200K emits 16 times more radiation than at 100K, not double. The discussion highlights the importance of using the correct equations related to blackbody radiation. Understanding these principles is crucial for solving related physics problems.
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Homework Statement



Does a blackbody at 200K emit twice as much total radiation as when its temperature is 100K?

Homework Equations



N/A

The Attempt at a Solution



I'm not sure, but I think it is yes because if the temperature is doubled, then the energy of the photons will be doubled, therefore it will emit twice as much radiation. Is this correct?
 
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There is a well-known equation that relates radiated power to temperature of a blackbody. It is surely in you class notes or textbook.
 
the only equation in my notes with temperature in it is:
(wavelength) x temperature = 0.002898mK

i don't know how this relates to the question though
 
There should be another equation, involving radiated power. And temperature raised to some integer power. It probably has a Greek lowercase "sigma" in it as well.

If not in your notes, check the textbook.
 
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