TheAntiRelative said:
What determines depth in a gravitational field? I don't entirely follow.
Pervect:
I don't actually have the book, thanks for some info on it. Do they give the reference for the publication of the experiment?
It sounds like you are recapping that there is no time effects from the acceleration but there is, of cource, the expected kinematic shift.
I'm just trying to fully grasp the difference between acceleration and depth in a gravitational field. How/why intensity does not matter...
The reference was to Farley, et al, "The anomalous magnetic moment of the negative muon", Nuovo Cimento 45, 281-286"
I'm not at all familiar with Nuovo Cimento, it's apparently an Italian physics journal. Google finds it online at http://paperseek.sif.it/ , but not for the years in quesiton.
To really understand how gravity causes time dilation in GR, you need to understand the GR concept of a metric.
Hopefully you've heard of the Lorentz interval from special relativity? This is the quantity
dL^2 = dt^2 - dx^2 - dy^2 - dz^2
This quantity is the same for all observers in any inertial frame of reference, no matter what their velocity.
In General Relativity, this is modified slightly. We compute the Lorentz interval via means of a metric, for instance it might be
dL^2 = g_{00} dt^2 - g_{11} dx^2 - g_{22} dy^2 - g_{33} dz^2
The metric coefficients in the above expression area the g_ij. In general, they (the metric coefficients g_ij) are functions of the coordinates.
The above equation (with some additional cross-terms which I've omitted such as g_01 dx dt, etc. ) is completely general and is valid for any coordinate system whatsoever, not just an inertial frame, via the proper choice of the coefficeints g_ij.
You may or may not recognize the above expression as a "quadratic form" from linear algebra.
Anyway, suppose that an object is not moving in space, and is in an inertial frame. This implies that we use the SR form of the expression for the Lorentz interval, and that dx,dy, and dz are all zero.
We are left with dL^2 = dt^2. So we see that the Lorentz interval dL is just the time interval for an object that is in an inertial frame and not moving.
Now, what happens when we switch to GR, and consider an object that is not moving in some general coordinate system? We find that dL^2 =g_00 dt^2. This means that g_00 plays the role of a time dilation factor. g_00 less than 1 imply "gravitational time dilation".
What's really important is that the Lorentz interval is the same for all observers, this is the basis of relativity.
The various forms of "time dialtion" are just a consequence of this fact. In the rest frame of an inertial particle, dL^2 = dt^2 and we have no time dilation.
If we go to a moving frame of reference, dL^2 = dt^2 (1 - (dx/dt)^2 - (dy/dt)^2 - (dz/dt)^2), and we see that we have velocity induced time dilation.
If you concentrate on the words, different coordinate systems all attribute time dilation to different phenomenon, and it can be confusing.
If you focus on the Lorentz interval, all becomes clear. The Lorentz interval is the same for all observers, and the various explanations of "time-dilation" are all a consequence of this fact plus the exact defintion of the coordinate system being used.