Does ef|g Imply e and f Are Both Factors of g?

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I was wondering if this is a correct statement, I'm assuming it is for my proof.

Let e,f and g be non zero integers and assume ef|g is true.

I'm 100% positive this means e and f must both be a factor of g .

May some one please confirm if I am correct or wrong please.
 
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hi blastoise! :wink:
blastoise said:
Let e,f and g be non zero integers and assume ef|g is true.

I'm 100% positive this means e and f must both be a factor of g .

you're 100% right! :smile:

(generally, if a|b and b|c, then a|c)
 

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