Does Every Field Have a Subfield Isomorphic to Q or Z mod p?

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SUMMARY

Every field contains a prime subfield that is isomorphic to either the rational numbers (Q) or the finite field Z mod p, depending on the field's characteristic. The prime subfield is defined as the intersection of all subfields of the given field. If the characteristic is 0, the subfield is isomorphic to Q; if the characteristic is a prime p, it is isomorphic to Z mod p. This conclusion is supported by the properties of fields and their subrings.

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  • Understanding of field theory and characteristics of fields
  • Knowledge of prime subfields and their properties
  • Familiarity with isomorphism in algebra
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ECmathstudent
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I just wrote an exam in Algebra II, and one of our true or false questions got me thinking. Does every field have a subfield which is isomorphic to the Q or Z mod p? I put it as true, for the wrong reasons, vaguely remembering a similar statement about integral domains and mixing it up. So, after the exam I was sure I was wrong.
But doesn't every field have the subfield {0,1}? Wouldn't this make the statement true, if somewhat vacuously?
 
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it's called the prime subfield, which is the intersection of all subfields of the given field. it's isomorphic to Q or Z_p depending on whether the field has characteristic 0 or p
 
Oh, thanks. I don't have a book anymore, when I tried to look it up on google I wasn't really getting any results.
 
yes.

it is quite easy to show this.

suppose 1+1+...+1 (n times) = 0.

then the subring generated by 1 is isomorphic to Zn.

however, since F is a field, none of the elements:

1, 1+1, 1+1+1, etc. can be a zero-divisor, which forces n to be prime.

on the other hand, suppose that n1 is never 0, for all n in Z+.

then the subring generated by 1 is isomorphic to the integers, and

any field containing the integers also contains the field of quotients of the integers, which is Q.

(also {0,1} is not a field, unless 1+1 = 0).
 

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