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Jameseyboy
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Homework Statement
In a constant temperature process, where heat is added - Does the enthalpy after the heat is added equal the initial enthalpy plus the Q value?
No problem. If you have saturated vapor and saturated liquid in equilibrium at a given quality, temperature, and pressure, and you add or remove heat so that the quality changes, then Q = ΔH (provided you don't add or remove enough heat to take you out of the two phase region). Also, ΔS=Q/T.Jameseyboy said:For my particular question I have steam with a given pressure and dryness fraction. Really not sure what to do here
Enthalpy is a thermodynamic quantity that measures the total energy of a system. It takes into account both the internal energy and the amount of work required to change the system's pressure and volume.
Constant temperature refers to a system or process in which the temperature remains the same throughout. This means that the amount of heat added to the system is equal to the amount of heat lost, resulting in no change in temperature.
At constant temperature, the change in enthalpy (ΔH) is equal to the heat added or removed from the system (Q). This is known as the enthalpy of reaction and is commonly used in thermodynamic calculations.
Enthalpy at constant temperature can be calculated using the formula: H = U + PV, where H is the enthalpy, U is the internal energy, P is the pressure, and V is the volume of the system.
Yes, enthalpy can be negative at constant temperature. This means that the system has released heat to its surroundings, resulting in a decrease in enthalpy. Negative enthalpy values are commonly seen in exothermic reactions.