Does the 0 vector not count when determining the dimension?

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SUMMARY

The discussion clarifies that the dimension of a vector space is determined by the number of linearly independent vectors it contains. Specifically, if the kernel of a linear transformation T, denoted as ker(T), consists solely of the zero vector, then dim(ker(T)) equals 0. The zero vector is present in every vector space but does not contribute to the dimension, which is defined by the presence of independent vectors.

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If we have ker(T)={0}, why is the dim(ker(T)) = 0?

Does the 0 vector not count when determining the dimension? I thought the answer would be 1.
 
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Nope, doesn't count. The zero vector is in any vector space. Even a one-dimensional space has the zero vector in it. The zero vector isn't what makes it one-dimensional.
 

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