Does the Charge on NOS Affect the Charge on Fe?

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The discussion centers on the oxidation states of iron in the reaction between Na2S and Na2[Fe(CN)5(NO)], leading to Na4[Fe(CN)5(NOS)]. Initially, iron is in the +2 oxidation state, but there is uncertainty about whether it becomes +3 after the reaction and the charge of NOS. The net charge of the reactant [Fe(CN)5(NO)] is -2, while the product [Fe(CN)5(NOS)] has a net charge of -4, suggesting that iron remains +2 in the product. The oxidation states of iron can vary, and the discussion emphasizes the importance of understanding octahedral geometry and charge distributions in coordination compounds. Clarification on the charge of NOS is needed to fully determine the oxidation state of iron in the product.
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Homework Statement


There is a reaction given in my textbook which says:
##Na_2S+Na_2 [Fe(CN)_5 (NO)]## ## \longrightarrow## ## Na_4 [Fe (CN)_5 (NOS)]##
I know initially Fe is in +2 state.
But does it become +3 charged after the reaction? What is the charge on NOS? Is it ##NOS^{-1}## or ##NOS^{-2}##?

Homework Equations

The Attempt at a Solution


I don't know... charge on ##Fe## depends upon the charge on ##NOS##... which I don't know.
Any help appreciated.
 
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I don't know how much I can help without getting castigated by admin, but I will risk it... The [Fe(CN)5(NO)] = -2 net charge and [Fe(CN)5(NOS)] = -4 net charge. Both are octahedral coordination structures with Fe+4 + 2e- => Fe+2 as the reduction and sulfur in Na2S is -2 charge being oxidized to So in the -NOS structure. Both -NO and -NOS have the same oxidation states = -1. Look up octahedral geometry, place CN (= -1 charge) on all points in the plane and one above the plane. The -NO and - NOS are each below the plane. With all the points -1 = -6 and Fe+4 in the reactant side = net -2 for the reactant anion. Draw the same structure with all points -CN and one -NOS => -6 again on the product side, but Fe in the product structure is +2. Then [(-6) + (+2)] = -4 for the product anion structure. Hope I don't get fussed at. Good luck.
 
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Thanks for your reply. I had some doubts:
##Fe## has two stable states... ##Fe^{+2}## and ##Fe^{+3}##. From where ##Fe^{+4}## came? Originally the compound has ##Fe^{+2}##.
 
mooncrater said:
Thanks for your reply. I had some doubts:
##Fe## has two stable states... ##Fe^{+2}## and ##Fe^{+3}##. From where ##Fe^{+4}## came? Originally the compound has ##Fe^{+2}##.
+2 and +3 oxidation states for iron are the most common, but actually, iron can have eight (8) oxidation states depending on the compound and structure it is associated with... Here's a link that may help on this... http://en.wikipedia.org/wiki/Iron ... Scroll down to 'Atomic Properties', there will be a list of the possible oxidation states for iron.

Did you look up the octahedral geometry for coordination compounds? Follow my suggestion about placing the substrates as suggested, then check the net charges.
 
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Here's Iron in an Octahedral Geometry for FeCl3-. The [Fe(CN)5(NO)]2- and [Fe(CN)5(NOS)]4- follow the same configurations.
upload_2015-5-13_0-52-16.png
 
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mooncrater said:

Homework Statement


There is a reaction given in my textbook which says:
##Na_2S+Na_2 [Fe(CN)_5 (NO)]## ## \longrightarrow## ## Na_4 [Fe (CN)_5 (NOS)]##
I know initially Fe is in +2 state.
But does it become +3 charged after the reaction? What is the charge on NOS? Is it ##NOS^{-1}## or ##NOS^{-2}##?

Homework Equations

The Attempt at a Solution


I don't know... charge on ##Fe## depends upon the charge on ##NOS##... which I don't know.
Any help appreciated.
Hey guy, how you doing on the problem? Just checking if all is OK. Hope I've helped. jp
 
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