Does This Line Integral Depend Only on Its End Points?

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Homework Statement



Show that the following line integral depends only on the end points of C by using a suitable theorem.

Then evaluate without parameterising it.

Homework Equations



\int_{(0,0)}^{(3,2)} 2xe^y dx + x^2e^y dy

The Attempt at a Solution



Is this the theorem...

\displaystyle \int F(x,y) dr =\int_C \frac{\partial \phi}{\partial x} dx +\frac{\partial \phi}{\partial y} dy =\int_a^b (\frac{\partial \phi}{\partial x} \frac{dx}{dt} +\frac{\partial \phi}{\partial y} \frac{dy}{dt}) dt...?
 
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do you know about conservative functions and vector fields ?
 
lanedance said:
do you know about conservative functions and vector fields ?

Yes, this force vector field is conservative because g_x=f_y, hence is independent of path C..but I don't know what theorem to use?
 
how about the gradient theorem
 
lanedance said:
how about the gradient theorem

It must be simpler than I thought

I calculate the potential function \phi (x,y)= x^2 e^y +C. we know the gradient of the potential function is the force vector field given in the question. I integrated backwards to get the potential, s I guess that's the theorem..right?

I evaluate the force field to be 9e^2...based on \displaystyle \int \nabla \phi \dot dr = \phi(x_1, y_1) - \phi (x_0, y_0)...
 
looks good
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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