How Fast is the Bat Flying Based on Doppler Effect and Beat Frequency?

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In summary, using the equations for frequency of beats and the speed of sound, we can solve for the speed of the bat as it approaches the wall. By isolating the variable f2 and equating the two equations, we can find that the speed of the bat is 17.5 m/s.
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moronto
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Homework Statement


A bat emits a sound at a frequency of 37.0 kHz as it approaches a wall. The bat detects beats with a frequency of 832 Hz between the sound it emits and the echo bouncing from the wall. What is the speed of the bat? (The speed of sound is 335 m/s.)


Homework Equations


f_beat = |f1 - f2|
f1 = (1/1-vbat/v)f When the Bat is the source approaching the wall
f2 = (1+vbat/v)f1 When the Bat is the observer and the sound is echoed off the wall


The Attempt at a Solution


832 = |f1 - f2|
f1 = 832+f2
So essentially i have two equations, two unknowns
832+f2 = (1/1-vbat/335)37000
f2 = (1+vbat/335)832+f2
Worked to isolate f2 in both equations and equated them together, now this seems to be way too much work... numbers were huge and even when i worked it through the answer was wrong, What is wrong with my approach?
 
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  • #2


Your approach is correct, but you made a mistake in your equations. The correct equations should be:

f1 = (1/(1-vbat/335))37000
f2 = (1+vbat/335)f1

By plugging these into your calculator, you should get vbat = 17.5 m/s.
 
  • #3


Your approach is on the right track, however, there are a few mistakes in your equations. First, the equation for the frequency of the beats should be f_beat = |f1 - f2|, not f_beat = |f1 + f2|. This is because the beats are caused by the difference in frequency between the sound emitted by the bat and the echo bouncing off the wall.

Second, in your equations for f1 and f2, you have included the frequency of the sound emitted by the bat (37.0 kHz) instead of the frequency of the beats (832 Hz). The correct equations should be f1 = (1/1-vbat/335)832 and f2 = (1+vbat/335)832.

Once you have corrected these mistakes, you should be able to solve for the speed of the bat using the equation for the speed of sound in air, v = fλ, where f is the frequency and λ is the wavelength. Remember to convert the frequency from kHz to Hz before plugging it into the equation. I hope this helps!
 

What is the Doppler Effect?

The Doppler Effect is the change in frequency or wavelength of a wave in relation to an observer who is moving relative to the source of the wave. This effect can be seen in sound waves, light waves, and even water waves.

How does the Doppler Effect create beats?

When two waves with slightly different frequencies overlap, they create a beat frequency, which is the difference between the two frequencies. This is known as the "beat" or "beat note" and can be heard as a pulsing sound.

What is the formula for calculating the Doppler Effect?

The formula for calculating the Doppler Effect is: f' = f (v +/- vo) / (v +/- vs), where f' is the observed frequency, f is the emitted frequency, v is the speed of the wave, vo is the observer's velocity, and vs is the source's velocity. This formula works for both moving observers and moving sources.

How is the Doppler Effect used in real life?

The Doppler Effect has many practical applications in everyday life. It is used in weather radar to detect the velocity and direction of storms, in medical ultrasound to measure blood flow, and in police radar guns to measure the speed of moving vehicles.

What is the difference between the Doppler Effect and the Doppler Shift?

The terms "Doppler Effect" and "Doppler Shift" are often used interchangeably, but there is a slight difference between the two. The Doppler Effect refers to the change in frequency or wavelength of a wave, while the Doppler Shift specifically refers to the change in frequency or wavelength of light waves. However, both terms are commonly used to describe the same phenomenon.

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