Dot product of a vector with the derivative of its unit vector

hoopsmax25
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Homework Statement


Let c(t) be a path of class C1. Suppose that ||c(t)||>0 for all t.
Show that c(t) dot product with d/dt((c(t))/||c(t)||) =0 for every t.


Homework Equations


I am having trouble with the derivative of (c(t)/||c(t)||) and how to show that when its dotted with c(t) that it always equals zero.


The Attempt at a Solution


I know that c(t) dotted with c'(t) =0 when ||c(t)||= a constant but don't know how to implement this fact for this problem.
 
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If d(t)=c(t)/||c(t)||, what is ||d(t)||?
 
What is the magnitude of c(t)/||c(t)||?
 
would it be 1?
 
hoopsmax25 said:
would it be 1?

Show why it is 1. Then you can drop the '?'.
 
Ok i get that now. So if d(t)=1, which is a constant, then d(t) dotted with d'(t) =0. Since c(t)/||c(t)|| has the same direction as c(t), we can then plug c(t) in for d(t). Does that make sense to do?
 
hoopsmax25 said:
Ok i get that now. So if d(t)=1, which is a constant, then d(t) dotted with d'(t) =0. Since c(t)/||c(t)|| has the same direction as c(t), we can then plug c(t) in for d(t). Does that make sense to do?

Makes sense to me.
 
Awesome. Thanks for the help
 
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