- #1
Phat
- 5
- 0
We got:
solve by x.
y^3+x^2y^2-y*sinx=1
derivate:
3y^2*y' + 2xy^2 + 2yx^2*y' - (y'sinx + ycosx) = 0
but to derivate this once again I am not sure how to proceed.
My solution:
[3y^2*y'+6y*y''] + [2y^2 + 4xyy'] + ...
solutoin manual:
6y*y'' + 2x2yy' + [2x^2*1*y'+2x^2*y*y'']
I've been searching for websites where I can read about this, but no luck.
What I think is done in the solution manual is that when x is x^1 it cannot be further derivated, because we kinda "loose" information?
I need some guidance or explination on how to handle equations that got:
y*y'
x*y^2
x*y*y'
Thanks in advance!
solve by x.
y^3+x^2y^2-y*sinx=1
derivate:
3y^2*y' + 2xy^2 + 2yx^2*y' - (y'sinx + ycosx) = 0
but to derivate this once again I am not sure how to proceed.
My solution:
[3y^2*y'+6y*y''] + [2y^2 + 4xyy'] + ...
solutoin manual:
6y*y'' + 2x2yy' + [2x^2*1*y'+2x^2*y*y'']
I've been searching for websites where I can read about this, but no luck.
What I think is done in the solution manual is that when x is x^1 it cannot be further derivated, because we kinda "loose" information?
I need some guidance or explination on how to handle equations that got:
y*y'
x*y^2
x*y*y'
Thanks in advance!