Evaluate [itex]\int\int[/itex]D(x+2y)dA, where D is the region bounded by the parabolas y=2x2 and y=1+x2
dA = r*drd[itex]\vartheta[/itex]
The Attempt at a Solution
Well, I know I need to put D into polar coordinates, but I'm lost on this one. The examples I have seen before involve D being a region like x2+y2 = 16, which I could easily turn in to 0[itex]\leq[/itex]r[itex]\leq[/itex]4 and 0[itex]\leq[/itex][itex]\vartheta[/itex] [itex]\leq[/itex]2[itex]\pi[/itex]
So, any advice on getting better at setting up these regions in terms of polar coordinates?
EDIT: Is r from 0 to 2 and theta from 0 to pi?