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Double Slit question

  1. May 19, 2006 #1
    Hello

    Could someone please help me with this question,,I have no idea how to work it out and have looked through my text book/notes and arrrr still can't do it...

    A beam of photons encounters a double slit that has a separation distance d = 34.0 μm. Note: the diagram is not drawn to scale...(the diagram just shows a slit with a detector array 'x' meters away)

    a)...if a single photon in the beam has an energy of 16.81x10^-19J what is it's energy in eV?

    I calculated that to be 10.5eV but then its the next one I cant do as I have no other info. besides seperation distance and energy!!!

    b) What is it's wavelength?
    ???????

    Any help would be much appreciated
    Thank you
    physics_06er
     
  2. jcsd
  3. May 19, 2006 #2
    You have to show your work here first.

    The two questions are very easy. Go through your Modern Physics textbook/course notes again...you're missing something.
     
  4. May 19, 2006 #3

    Chi Meson

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    I think this is enough of a hint: there was a guy named Max Planck...
     
  5. May 19, 2006 #4

    Hootenanny

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    :rofl: :rofl: :rofl: And he lived in a land far far away.... :tongue2:

    ~H
     
  6. May 19, 2006 #5

    Chi Meson

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    Then one day, the morning after the ultraviolet catastrophe erupted...
    ...
    nah!

    Sorry, back to the thread. What is the thing Planck is most remembered for?
     
  7. May 19, 2006 #6

    Hootenanny

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    Yes, I think this thread has become a little tangental. We should wait for the OP to return before we continue our story :biggrin:

    ~H
     
  8. May 19, 2006 #7
    Hi there

    Thanks for the help

    so I just found Freq using E=hf and then wavelength using c=f.lamda coming up with 1.18e-7m

    Thanks again
    physics_06er

    ...You guys can carry on your story if you wish :approve:
     
  9. May 20, 2006 #8
    Hello there...so I worked out how to to the angle question...however can someone pls check my working...by the way I made a mistake in my first post the seperation distance is 38.0micrometres

    ...so to find the freq. i used E/h ..16.81e-19/6.63e-19=2.535444947Hz then I went 3e8/2.535444947 and got 118322427.1 (its in meters right)..well the answer says 0.118nm??? What have I done wrong...

    Next for the angle question i used dsintheta=(m+0.5)lamda and got an angle of 0.089...however this is when I use the answer they have given me...someone please tell me where I have gone wrong?
     
    Last edited: May 20, 2006
  10. May 20, 2006 #9
    seems my angle question was deleted...but the question was if the detector array is placed 3.0m behind the double slit determine:...the angle m=0 destructive interference which is the one I have answered above---and also this one I hav NO idea how to do...determine the distance above the center of the interference pattern..I dont even know what they are asking?
     
  11. May 23, 2006 #10

    re-check your value for h.... I haven't done the calculations, but it should put you in the right ball park
     
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