Doubt with Ampere and Biot-Savart

AI Thread Summary
Ampère-Maxwell and Biot-Savart laws both describe magnetic fields but are applied differently. The Biot-Savart law requires careful treatment of the integration variable, particularly in the denominator, which depends on the position along the wire. For line currents, the Biot-Savart law simplifies from a volume integral to a line integral. Both laws share a similar mathematical structure, highlighting their foundational role in electromagnetism. Understanding the nuances of these equations is essential for accurate magnetic field calculations.
atomqwerty
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Hello,

I think I'm terribly wrong by supossing Ampère-Maxwell and Biot-Savart are referred to the same concept of magnetic field B. For example, for calculating B near an infinite line, I used both, as I understood them, obtaining different expressions (see image). What is that that I don't get?

Thanks
 

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You didn't do the Biot-Savart integral right. Let the wire go up the z-axis, and the integral is

B(\rho) = \int_{-\infty}^\infty \frac{\mu_0}{4\pi} \frac{I e_z \; dz' \times (\rho e_\rho - z' e_z)}{(\rho^2 + {z'}^2)^{3/2}}

You treated the denominator like it doesn't depend on z', but it does. I write it z' to emphasize that it is the integration variable (not the position we want to find the magnetic field at). Consult a table of integrals to easily find the antiderivative.

In general, for some current density j, the Biot-Savart Law is

B(r) = \int_{V'} \mu_0 j(r') \; dV' \times \frac{r - r'}{4 \pi |r - r'|^3}

Actual line currents (not densities) just reduce this integral from a volume to a line. Compare with the electric field from some charge density:

E(r) = \int_{V'} \frac{\rho(r')}{\epsilon_0} \; dV' \frac{r - r'}{4 \pi |r - r'|^3}

for vectors r, r'. You can see these are both really the "same" law. The function (r-r')/4\pi|r-r'|^3 has special significance in 3D space. Wiki "Green's functions" if you're interested in learning about it.
 
Thank you very much, that was really helpful, I appreciate it!

Carlos
 
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